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4 years ago

What is the slope of (-3,0) and (0,-6)

Mathematics

1 answer:

tresset_1 [31]4 years ago

3 0

Answer:

$m=-2$

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Simply plug in your 2 coordinates into the slope formula to find slope <em>m</em>:

$m=\frac{-6-0}{0-(-3)}$

$m=\frac{-6}{0+3}$

$m=\frac{-6}{3}$

$m=-2$

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In the figure above, arc RST measures 30°

Ivenika [448]

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4 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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3 years ago

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sergiy2304 [10]

Sorry can see good in the pic maybe next time
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3 years ago

Which lists all the integer solutions of the equation |x| = 10?

kakasveta [241]

There is no list and no choices given.

The solutions of | x | = 10 are x = 10 and x = -10 .

All (both) solutions happen to be integers.
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3 years ago

Read 2 more answers

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kicyunya [14]

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3 years ago