40L equals how many mL

If you add 12 to my number and then multiply the result by 3, you will get 64 more than two-thirds of my number. Find my number.

anastassius [24]

Answer:

The number is 12

Step-by-step explanation:

[] First, let's turn all these words into something mathematical. N will equal "my number"

-> If you add 12 to my number and then multiply the result by 3, you will get 64 more than two-thirds of my number.

-> n + 12 and then multiply the result by 3, you will get 64 more than two-thirds of my number.

-> 3(n + 12), you will get 64 more than two-thirds of my number.

-> 3(n + 12) = 64 more than $\frac{2n}{3}$

-> 3(n + 12) = 64 + $\frac{2n}{3}$

[] Phew, okay. Now it is something we can solve and less scary;

[Given]

3(n + 12) = 64 + $\frac{2n}{3}$

[Distribute]

3n + 36 = 64 + $\frac{2n}{3}$

[Multiply both sides by 3]

9n + 108 = 192 + 2n

[Subtract 108 and 2n from both sides]

7n = 84

[Divide both sides by 4]

n = 12

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0

3 years ago

HOW MANY MILES PER HOUR IS KM/HR (1 MILE = 1.61 KM

Yuliya22 [10]

Answer:

1 MPH = 1.61 KMHR

Step-by-step explanation:

For an approximate result, multiply the speed value by 1.609

3 0

3 years ago

What is 6/a-6 = 3/a-3 ? help me please

Alenkasestr [34]

Answer:

a=1

Step-by-step explanation:

Multiply all terms by a and cancel:

6+−6a=3+−3a

−6a+6=−3a+3(Simplify both sides of the equation)

−6a+6+3a=−3a+3+3a(Add 3a to both sides)

−3a+6=3

−3a+6−6=3−6(Subtract 6 from both sides)

−3a=−3

−3a

−3

=

−3

(Divide both sides by -3)

a=1

3 0

3 years ago

Read 2 more answers

the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?

olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be $\frac{123}{40}$

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= $\frac{-3y}{y-1}$

Similarly fourth term will be

x-3y-2y=x-5y

$x-5y=\frac{x}{y}$

substitute the value of x in the equation

$\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0$