Question

An archer hits the center of the target (the bullseye) 70 percent of the time. However, she is a streak shooter, and if she hits the center on one shot, her probability of hitting it on the shot immediately following is 0.85. Written in probability notation: P(A) = P(B) = P (hitting the center on one shot) = 0.70 P(B|A) = P (hitting the center on a second shot, given that she hit it on the first) = 0.85 Calculate the probability that she will hit the center of the target on two consecutive shots.

Answer 1

Answer:

0.595

Step-by-step explanation:

We are given that An archer hits  centre of the target

We have to calculate the probability that she will hit the centre of the target on two consecutive shots.

P(A)=P(B)=0.70

P(B/A)=0.85

We know tha formula

$P(B/A)=\frac{P(A\cap B)}{P(A)}$

Substitute the value then we get

$P(A\cap B)=P(B/A)\cdot P(A)=0.85\times 0.70=0.595$

Hence, the probability that she will hit the centre of the target on two consecutive shots=0.595