Answer:

Step-by-step explanation:
Given

Required
The average rate over ![[2,b]](https://tex.z-dn.net/?f=%5B2%2Cb%5D)
Average rate (m) is calculated using:

Where
![[a,b] = [2,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B2%2Cb%5D)
So, we have:

Calculate f(b) and f(2)



So, we have:



Expand the numerator

Factorize

Factor out 3b + 6

Cancel out b - 2

Answer:
<em><u>$18.50</u></em>
Step-by-step explanation:
$647.50 ÷ 35 (as its the hours they work).
You do this to find the value of one hour..
= $18.50 Every hour!
Answer:
I think 49 im not sure
Step-by-step explanation:
dont trust me I not good with math
Answer:
If n = 1000000, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If n = 10400, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If N = 102, then

Step-by-step explanation:
Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2
The density function of that random variable is given by de following formula

If n = 1000000, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If n = 10400, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If N = 102, then

Answer:
8 i believe
Step-by-step explanation: