Question

A coffee mixture has beans that sell for $0.08 a pound and beans that sell for $0.32. If 110 pounds of beans create a mixture worth $0.44 a pound, how much of each bean is used? Model the scenario then solve it. Then, in two or more sentences explain whether your solution is or is not reasonable.

Answer 1

Answer:

$0,08 bean= -65 pounds

$0,32 bean= 165 pounds

Step-by-step explanation:

we need to understand that the sum of 2 values is not going to be higher than any of those to values

Maybe the numbers have an error

According to the text we can have to expressions just we need to understand it

The problem says beans x + beans y = 110 pounds of mixture

From this we have the first expression x+y=110

Then a mix of the two kind of beans produces a mixture worth $0,44

From this we have the second expression 0,08(x)+0,32(y)=0,44(z)

z is the weight of the mixture and we know it is 110 pound

0,08(x)+0,32(y)=48,4

x=pounds of the first bean

y=pouns of the second bean

Now we need to solve one and pu it into the other

x=110-y

0,08(110-y)+0,32(y)=48,4

8,8-0,08y+0,32y=48,4

0,24y=39,6

y=165

x=110-165=-65