At least two body systems are needed to perform the function of breathing because to ensure breathing, the body performs two respiratory movements: inspiration, which is the entry of air into the lungs, and expiration, which is the elimination of carbon dioxide. Pulmonary breathing is a process in which air enters our lungs and is subsequently eliminated. involving muscles and gaseous reactions.
<h3>What is the path of air inside the human body?</h3>
The air penetrates through the nasal passages, passes through the pharynx, larynx and trachea, bronchi, reaching the lungs where it travels through the bronchioles until reaching the alveoli, where gas exchange takes place. The difference between inspired and expired air is in the concentration of oxygen and carbon dioxide.
With this information, we can conclude that The entire process of gas exchange in the body, which is called breathing, takes place in three basic steps, which are pulmonary ventilation, which corresponds to the flow of air in and out of the lungs.
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Answer:
600 cm³
Explanation:
Given data:
Length of box = 25 cm
Width of box = 6 cm
Height of box = 4 cm
Volume = ?
Solution:
Volume = Length × Width × Height
Volume = 25 cm × 6 cm × 4 cm
Volume = 600 cm³
The volume of box is 600 cm³ so it can hold same volume of water.
Answer:
brown hair
Explanation:
because all you had to do was look at it
Answer:
1. 2.8%
2. 97.1%
Explanation:
- If the birth rate of this disorder is 1 in every 5000 births it means that the frequency of the recessive homozygous genotype is 1/5000=0.0002
If we name the gene for the disorder with A, than the genotypes are aa (homozugous recessive), Aa (heterozygous, carrier), AA (dominant homozygous).
According to the Hardy-Weinberg equation:
frequency of AA is p2 (P)
frequency of Aa is 2pq
frequency of aa is q2 (Q) and
p2+2pq+q2=1 (P+Q=1)
Q=0.0002 P=1-0.0002=0.9998
q= 
0.0002=0.014
p=0.9998=0.999
2pq=0.028=2.8%
2. According to the Hardy-Weinberg equation:
frequency of AA is p2 (P)
frequency of Aa is 2pq
frequency of aa is q2 (Q) and
p2+2pq+q2=1 (P+Q=1)
The frequency of the recessive homozygous genotype (Q) is 1/5000=0.0002
Q=0.0002
q2=0.0002 2pq=0.028 p2=?
p2= 1-0.0002-0.028 =0.9718=97.1%
Answer:
Cellular differentiation is the process in which a cell changes from one cell type to another. Usually, the cell changes to a more specialized type.
Stem cells can become a variety of types of cells, while differentiated cells like red blood cells are fully specialized cell types. ... A stem cell produces a mesoderm cell, which can then further differentiate to form a muscle stem cell. From there it differentiates into a smooth muscle cell.
