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frozen [14]
3 years ago
7

en una guardería ay una matricula de 50 lactantes de los cuales 20 son niñas cual es la razon de niñas a niños en dicha guarderi

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Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
7 0

Answer:

La razón de niñas a niños en la guardería es de 2 niñas por cada 3 niños.

Step-by-step explanation:

Una razón es una división entre dos números, generalmente en forma racional (fraccionaria). La razón de niñas a niños en la guardería es la cantidad de niñas dividida por la cantidad de niños de la dicha guardería, Es decir:

x = \frac{20}{30}

x = \frac{2}{3}

La razón de niñas a niños en la guardería es de 2 niñas por cada 3 niños.

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Write an equation in slope-intercept form of the line having the given slope and y-intercept.
pychu [463]

Answer:

The answer to your question is   y = 4/6x - 4

Step-by-step explanation:

Data

m = 4/6

P (0, -4)

slope-intercept form = ?      y = mx + b    where m is the slope and

                                                                  b is the y-intercept

Formula

           y - y1 = m(x - x1)

Substitution

           y - (-4) = 4/6(x - 0)

Simplification

           y + 4 = 4/6x

Result

                 y = 4/6x - 4

slope = 4/6  y-intercept = -4

7 0
3 years ago
lisha is making headbands using ribbon. she would like to make 12 head bands. Each one requires 15.5 inches of ribbon. She estim
katrin2010 [14]
No her estimate is to low because if you multiply 15.5 by 12 you get 186
8 0
4 years ago
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Helpppppppp pweaseeeee
AlladinOne [14]

length=6

breath=15

height=12

therefore,12+3+15

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6 0
3 years ago
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PLEASE HELP WITH EXPLAINING I WILL MARK BRAINIES!!!
Drupady [299]

Answer: 3 mph

Step-by-step explanation:

1. 1/2 mph for 1/2 an hour as they said, meaning that they would've walked for 3 miles kn an hour.

2. 4 and 1/2 miles.

3 + 1 2/4. = 4 1/2

3. 1 3/4 hours.

3 + 2.25 = 5.25

3 x .75 = 2.25

3 miles per hour.

8 0
3 years ago
The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the
Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

  • a +b +c = 26
  • 2a -b = c -2
  • -3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

_____

The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

6 0
4 years ago
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