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scZoUnD [109]
3 years ago
11

Which of the following is another name for a line of longitude

Geography
2 answers:
Phoenix [80]3 years ago
8 0
A) meridian i think
vesna_86 [32]3 years ago
5 0

Answer: meridian hope that helped!

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The headwaters of a river are at an elevation of 1,229 feet and the river flows 373 miles to the ocean. Determine the river's av
AlekseyPX

Answer:

3.29ft/mi

Explanation:

The gradient of a river is the slope through which a river flows. It measures the vertical drop in elevation of river to the horizontal distance.

 Mathematically;

  River gradient = \frac{Elevation}{horizontal distance}  

 Elevation  = 1229ft

Horizontal distance  = 373miles

  River gradient  = \frac{1229}{373}   = 3.29ft/mi

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Evidence that the earth spins on it axis
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  • Earth rotates eastward, in prograde motion.
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In nuclear fission and fusion reactions mass is converted into energy. The average person in US uses around 100,000,000 J of ene
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Answer:

a) The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) The energy that would be released if a 60 kg person were converted entirely into energy is 5.4\times 10^{18} Joules.

c) 180 years would this amount of energy support a population of 300 million.

Explanation:

a) Average energy consumed by single person of US = 100,000,000 J/year

Then 300 million US citizen will consume:

300 million = 300 × 1,000,000 = 3\times 10^8

The yearly energy consumption for a US population :

100,000,000 J/year\times 3\times 10^8=3\times 10^{16} J/year

The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) E = m\times c^2

E = Energy from converted mass of m

c = speed of light

Given mass of person = m = 60 kg

E=60 kg\times (3\times 10^8 m/s)^2 = 5.4\times 10^{18} J

c) Energy calculated in part (b) = E=5.4\times 10^{18} J

The yearly energy consumption for a US population  of 300 million in an year = 3\times 10^{16} J/year

Let the that would be supported by 5.4\times 10^{18} Joules of energy be x.

x\times 3\times 10^{16} J/year=5.4\times 10^{18} J

x=\frac{5.4\times 10^{18} J}{3\times 10^{16} J/year}=180 years

180 years would this amount of energy support a population of 300 million.

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