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Virty [35]
3 years ago
15

Can the sides of a triangle have lengths 2,6, 9?

Mathematics
1 answer:
frutty [35]3 years ago
6 0

Answer:

No

Step-by-step explanation:

Using the Pythagorean theorem,  a squared + b squared = c squared, where c is the hypotenuse. 2 squared is 4, 6 squared is 36. 4+36 is 40, but 9's square is 81. This means that it can't be a triangle.

Hope this helps :)

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FInd the value of C.
My name is Ann [436]

Answer:

The side C equals to 10. hence the answer is letter A

Step-by-step explanation:

To solve this, we need to use trigonometric functions.

we know that sin (α) = Lo / H for a triangle. Being Lo : Length of the opposite side and H: Length of the hypotenuse.

Given α= 45º and Lo= 5√2 and replacing in the equation:

sin (45º) = 5√2 / C (1)

Using trigonometric identities we know that sin(45º) =(√2)/2. Replacing in equation (1):

sin (45º) = (√2)/2 = 5√2 / C ⇒ C = 2 *5 *√2 / (√2) ⇒ C=10

6 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS IM BEGGING U
Artyom0805 [142]

Answer:

A

Y-Intercept is -2

X then Y so it would be -2,-4

7 0
2 years ago
Read 2 more answers
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
What is the probability of getting a sum of 6, given that one die shows a 5? Question 1 options: 5/36 11/36 2/11 5/11
alisha [4.7K]

There are 11 ways a pair of dice can show a 5. Of those, 2 have a sum of 6.

Your probability is 2/11.

5 0
3 years ago
PLEASE HELPPPPP ASAP
saul85 [17]

Answer:

it's the last one, the function is decreasing from x=-3 to x=-1

5 0
3 years ago
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