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3 years ago

Which function best models the data?

Mathematics

1 answer:

Virty [35]3 years ago

3 0

Answer:

y = 9,958(0.972)^t

Step-by-step explanation:

From point to point, the difference in days is always constant (10 days), but the difference between estimated number of bees is not constant.

10000 - 7500 = 2500

7500 - 5600 = 1900

5600 - 4200 = 1600

4200 - 3200 = 1000

3200 - 2400 = 800

Therefore, the data don't fit a line.

From the other two options:

y = 9,958(0.972)^t

y = 0.972(9,958)^t

only the first one has sense, because its initial amount of bees is 9,958 (near to 10,000) and in the second option is 0.972.

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Is the expression 3x+2x−4 in simplest form

stich3 [128]

No, because you would have to simplify like terms. Which the simplest form would be
5x-4

7 0

3 years ago

Read 2 more answers

A coach for a little league baseball team is ordering trophies for the team. Players on the team are allowed to choose between 2

Natali5045456 [20]

Answer:

y= 5.99(g) + 6.49(u)

Step-by-step explanation:

1) First you determine the variable in the equation $5.99, $6.49, g, and u.

2) Then analyze the equation and identify that each gold baseball trophy (g) is worth $5.99, and each uniform baseball trophy (u) is worth $6.49 each.

3) Since you are finding the total you insert a plus sign.

8 0

3 years ago

2) The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart. A student as

Serggg [28]

Answer:

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

Step-by-step explanation:

Explanation:-

Step:- (1)

The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart.

A student asked a random sample of teachers in 2018 and found 165 had smart-phones, 80 had a cell phone

The first sample proportion

$p_{1} = \frac{80}{165} = 0.4848$

A student asked a random sample of teachers in 2018 and found 165 had smart-phones,5 had no cell phone

The second sample proportion

$p_{2} = \frac{5}{165} = 0.03030$

Step :-(ii)

Null hypothesis :H₀: Assume that there is no difference in the distribution of types of cell phones for the teachers in 2018

H₀ : p₁ = p₂

Alternative hypothesis :H₁

H₁ : p₁ ≠ p₂

Level of significance : ∝=0.05

The tabulated value z=1.96

Step:-(iii)

The test statistic

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } } +\frac{1}{n_{2} } )} }$

where $p = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1} + n_{2} }$

q = 1-p

In given data n₁ = n₂ = n

$p = \frac{165 (0.4848)+165 (0.03030 }{165 + 165}$

on calculation , we get p = 0.2655

q =1-p = 1-0.2655

q = 0.7345

$Z = \frac{0.4848 -0.030}{\sqrt{0.2655X0.7345(\frac{1}{165 } } +\frac{1}{165} )} }$

Z = 9.4451

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Conclusion:-

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

6 0

4 years ago

Suppose we wish to demonstrate that there is a difference between the proportions of wives and husbands who do laundry at home.

maxonik [38]

Answer:

Step-by-step explanation:

From this study:

The null hypothesis:

$H_o : p_1 =p_2$

The altenative is:

$H_a : p_1 \ne p_2$

This test is a two-tailed test.

However; we are told that the wives have 44 success out of 66, then the number of failures will be 22.

Then;

$\hat p_1 = \dfrac{44}{66}$

$\hat p_1 = 0.6667$

Similarly, the husbands have 18 success out of 46, then the number of failures will be 28

Then:

$\hat p_2 = \dfrac{18}{46}$

$\hat p_2 = 0.3913$

The pooled proportion $p = \dfrac{18+44}{66+46}$

$p = \dfrac{62}{112}$

p = 0.55357

The estimated standard error S.E is:

$= \sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}$

= $\sqrt{ 0.55357(1-0.55357) \Big( \dfrac{1}{66} + \dfrac{1}{46} \Big)}$

$=\sqrt{ 0.55357(0.44643) \Big(0.01515 + 0.021739 \Big)}$

$=\sqrt{ 0.00911638798}$

= 0.0955

The Z test statitics can now be computed as:

$Z = \dfrac{ \hat p_1 - \hat p_2}{\sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}}$

$Z = \dfrac{0.6667 -0.3913}{0.0955}$

Z = 2.88

Th p -value from the test statistics is:

p-value = 2P(Z > 2.88)

p- value = 2 P (1 - Z < 2.88)

p-value = 2 ( 1 - 0.998)

p-value = 2 ( 0.002)

p -alue = 0.004

Decision Rule:

Thus, at 0.01 significance level, we reject the null hypothesis because, p-value is less than that (i.e. significance level)

Conclusion:

We conclude that there is a significant difference between the proportions.

5 0

3 years ago

Simplify the following expression. 3(2k + 3) -8k + 5 + 5

saw5 [17]

Answer:

Step-by-step explanation:

3*(2k + 3) - 8k + 5 + 5 Remove the brackets on the left

6k + 9 - 8k + 5 + 5 Combine like terms

6k-8k+9 + 5 + 5

-2k + 19

5 0

3 years ago