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3 years ago

1 2 3 66 84 3 43 I need help

Mathematics

1 answer:

Alex787 [66]3 years ago

6 0

Answer:

m<1 = 30 degrees

m<2= 41 degrees

m<3= 96 degrees

Step-by-step explanation:

Hope this helps :)

Pls give brainliest, I really need it

- massmaster34

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What two represents quantities that are proportional A.30/36 and 40/46. B.40/48 and 100/120. C.4/9 and 14/19. D. 27/81 and 21/72

lubasha [3.4K]

The answer is 4/9 and 14/19

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3 years ago

Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form

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11 upon 4 (11/4)

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3 years ago

There are 32 forwards and 80 guards in Leo's basketball league.Leo must include all players on a team and wants each team to hav

jeka94

Answer: There are 5 guards on each team.

Step-by-step explanation:

Since we have given that

Number of forwards in basketball league = 32

Number of guards in basketball league = 80

We need to find the greatest number of teams possible.

We will find "H.C.F. of 32 and 80.

Since H.C.F. of 32 and 80 = 16

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7 0

3 years ago

Pls help I really need help pls I need Profesional at math pls pls

Rzqust [24]

I think $6.75 for 15 juice boxes is better because, each juice box is 0.45.

While $5.50 for 11 juice boxes is 0.50.

And if we were to add 0.50 enough times to make 15 juice boxes it would equal 7.50

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THE SECOND ONE IS A WAY BETTER OF A DEAL

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3 years ago

Julia is going to the store to buy candies. Small candies cost $4 and extra-large candies cost $12.She needs to purchase at leas

BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

3 years ago