The central part of the Earth below the mantle

59:15

jek_recluse [69]

Triple Alliance: Italy, Germany, Austria-Hungary

5 0

2 years ago

Give the boundaries of the indicated value. 6.09 miles

olasank [31]

Answer:

6.085 (lower bound)

6.095 (upper bound)

Explanation:

6.08 6.09 6.1

^ ^

6.085 6.095

5 0

3 years ago

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Fell : compassionate :: broken :

Shalnov [3]

Hotel: Trivago (I’m bored if you can tell lol)

8 0

2 years ago

can someone pls answer my question before this i really need help just picture yourself in this situation

Sergio039 [100]

Why is your question?

5 0

3 years ago

suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a

saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

 I hope this is understandable and if my answer helped you please can you give me a brainliest its will really help me and thank you have a nice day!!

3 0

2 years ago

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