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3 years ago

Based on the data provided, which type of transaction is likely to bring in the most income during a month?

Mathematics

1 answer:

adell [148]3 years ago

5 0

Answer:c

Step-by-step explanation:

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Plz help asap!!!!!!!!!!!

Illusion [34]

Answer:

The answer is b

Step-by-step explanation:

7 0

4 years ago

What is the m=<br> And what is the equation<br> Please help me asap its almost due

Alenkasestr [34]

Answer:

m = 1 $\frac{1}{7}$ , y = 1 $\frac{1}{7}$ x + 10

Step-by-step explanation:

The equation of a line is y = mx + c where m is the slope and c is the y-intercept. I will be calculating the slope using the points (7, 2) and (0, 10)

m = $\frac{rise}{run}$

= $\frac{2-10}{7-0}$

= $\frac{8}{7}$

= 1 $\frac{1}{7}$

Based on the graph, the y-intercept is 10. Thus, the equation of the line is 1 $\frac{1}{7}$ x + 10.

7 0

3 years ago

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11+11 im 4 i need help

MrRa [10]

1.) 11 + 11. Let's solve this in steps.

2.) 11 + 11 = 10 + 10 + 2

3.) 10 + 10 = 20

4.) 20 + 2 = 22

5.) 22 = answer

5 0

3 years ago

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Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago

Solve and graph the absolute value inequality: |2x + 1| ≤ 5.

bogdanovich [222]

|2x + 1| < = 5

-5 < = 2x + 1 < = 5 ...subtract 1
-5 - 1 < = 2x + 1 - 1 < = 5 - 1
-6 < = 2x < = 4 ....divide by 2
-6/2 < = (2/2)x < = 4/2
-3 < = x < = 2

B. a number line with closed dots (because of the = sign) on -3 and 2 with shading in between

6 0

4 years ago

Read 2 more answers