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ivann1987 [24]
3 years ago
13

What is the standard form of the equation of the circle x2 -4x + y2 + 6y + 12 = 0?

Mathematics
1 answer:
Rashid [163]3 years ago
4 0
We take the equation
                            <span>x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
                             </span><span>x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0</span>
<span>                                            (x-2)^2 - 4 + (y+3)^2 - 9 = -12</span>
<span>                                                       <span>(x-2)^2+ (y+3)^2  = 1
Therefore the answer is </span></span><span>(x-2)^2+ (y+3)^2  = 1</span>
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