Question

Worth 30 points please help). The tightrope walker tried to catch his phone and also fell but he fell safely on the safety net that is 11 feet above the ring how many seconds did it take for him to land on the net? h(t)=60-16t^2.

Answer 1

Answer:

Time it took for the walker to land on net = 1.75 seconds

Step-by-step explanation:

Given:

Height above the ring as a function of time is give as:

$h(t)=60-16t^2$

Height of the tightrope walker after he falls = 11 feet

Plugging the height in order to find the time it took for the walker to land on net.

$11=60-16t^2$

Adding $16t^2$ to both sides.

$11+16t^2=60-16t^2+16t^2$

$11+16t^2=60$

Subtracting both sides by 11.

$11-11+16t^2=60-11$

$16t^2=49$

Dividing both sides by 16.

$\frac{16t^2}{16}=\frac{49}{16}\\\\t^2=\frac{49}{16}$

Taking square root both sides.

$\sqrt t^2=\sqrt{\frac{49}{16}}\\\\t=\pm\frac{7}{4}$

Since time is always positive

∴ $t=\frac{7}{4} = 1.75 \ seconds$

∴ Time it took for the walker to land on net = 1.75 seconds