A dekameter is best suited for measuring which distance?
1 answer:
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Answer:
relative minimum
Step-by-step explanation:
From f^''(x) = 12x we can take the integration to find out what f'(x) is:
Furthermore, we can substitute x = 1 for f''(x) to find out whether it's positive or negative
f''(1) = 12*1 = 12 > 0
So if x=1 is a critical point of f'(x) and f''(x=1) > 0 then that point is a relative minimum point
Answer:
(2,3)
Step-by-step explanation:
The given equations are:
and
Equate both equations:
Multiply through by 2:
x=2
Put x=2 into the first equation:
y=3
The solution is (2,3)