Which statement about the ordered pairs (−9,3) and (2,−4) is true for the equation 6x−y2=14 ?

Mathematics

1 answer:

ehidna [41]4 years ago

5 0

Answer:

What are the statements to choose from? Send me a message with the choices.

Step-by-step explanation:

6x-2y=14

+2y +2y

6x=14+2y

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Find the value of the variable and yz if y is between x and z xy=5p yz=p xy=25

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P is 5 , so yz=5 that’s the answer

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Answer:

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Step-by-step explanation:

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iogann1982 [59]

Answer:
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Nadia bought 4.3 pounds of ham on Tuesday and 1.7 pounds of ham on Wednesday. She spent a total of $41.94. What was the price of

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Read 2 more answers

X^2-8x+16=5 what are the solutions?

svp [43]

Hey!

The first step to solving this equation would be to subtract 5 from both sides of the equation.

Original Equation :
$x^{2}$ - 8x + 16 = 5

New Equation {Added Subtract 5 to Both Sides} :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Now we solve our new equation.

Old Equation :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Solution {Old Equation Solved} :
$x^{2}$ - 8x + 11 = 0

The next step would be to solve with the quadratic formula.

Quadratic Equation ( 1 ) :
$x = \frac{-(-8) + \sqrt{(-8)^{2} -4 * 1 * 11 } }{2*1}$

Quadratic Equation ( 1 ) {Solved} :
4 + $\sqrt{5}$

Quadratic Equation ( 2 ) :
$x = \frac{-(-8) - \sqrt{(-8)^{2}-4 *1*11 } }{2*1}$

Quadratic Equation ( 2 ) {Solved} :
4 - $\sqrt{5}$

So, our final solutions for the equation $x^{2}$ - 8x + 16 = 5 are...

x = 4 + $\sqrt{5}$

and 

x = 4 - $\sqrt{5}$

Hope this helps!

- Lindsey Frazier ♥

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4 years ago