He wrote the number 1892, because:
The number needs to be less than 2000, with four digits. Because the first is half the last, it means that the number must be 1??2.
These two numbers add up to 3, and all together, they need to add to 20. 20-3=17. The remaining numbers need to add to 17.
The only two single digit numbers that can add to 17, are 8 and 9. Therefore, the number must either be 1892 or 1982.
The second digit needs to be even, meaning that the number has to be 1892.
I hope this helps.
Answer:
x=10, y=25
Step-by-step explanation:
First, in a trapezoid, the two angles on the same leg (the legs are the opposite sides that are not parallel) add up to 180 degrees. Therefore, 4y as well as (2y+3x) are supplementary. We can write this out as
4y + (2y+3x) = 180
6y+3x = 180
Next, the angles of a triangle add up to 180 degrees. Therefore, as the angles 2y, 4y, and (5x-20) make up a triangle, they add up to 180 degrees. We can write this as
4y + 2y + (5x-20) = 180
6y + 5x -20 =180
Our two equations are thus
6y + 5x - 20 = 180
6y + 3x = 180
If we subtract 6y from both sides in each equation, we can say
5x - 20 = 180-6y
3x = 180-6y
Therefore, we can write
5x-20 = 180-5y = 3x
5x-20=3x
subtract 3x from both sides to make all x variables on the same side
2x-20 = 0
add 20 to both sides to isolate the x and its coefficient
2x = 20
divide both sides by 2 to isolate x
x = 10
Therefore,
x = 10
6y + 3x = 180
6y + 30 = 180
subtract 30 from both sides to isolate the y and its coefficient
6y = 150
y = 25
Answer:
Its B, y=-0.89x^2+3.24x+11.93
Step-by-step explanation:
mark brainest pls
Answer:
TYSM!!!!!!!!!!!!!!!!
Step-by-step explanation:
THX!!!THX!!!THX!!!!!!!u r so awesome!!!!!!!!!!!!!!!!!!TYSM!!!!!!!!!
Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
