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andrew11 [14]
4 years ago
15

Find two numbers whose product is 8(5)=40 and whose sum is -14

Mathematics
1 answer:
irakobra [83]4 years ago
6 0
-8 and -5 is the answer
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State the inverse operation divide be 8
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tamaranim1 [39]
The correct answer is:  [C]:  " a =  ± \sqrt{25 - b^2}  " .
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:  
_________________________________________________________
    </span>→   "  25  =  a²  +  b²  "  ;   Solve for "a" ; 
_________________________________________________________

    →  To solve for "a" ;  we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite:  "  25  =  a²  +  b²  "  ;

as:  " a²  +  b²  = 25 " .

_________________________________________________________
Then, we can subtract " b² "  from each side of the equation; as follows:
_________________________________________________________

   →
 " a²  +  b²  −  b²  =  25 − b²  "  ;

to get:
_________________________________________________________
   →  " a²  =  25 − b²  "  ;
_________________________________________________________
  →  Now,  take the square root of EACH SIDE of the equation ; 
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ; 
_________________________________________________________

  →  √(a²)  = \sqrt{25 - b^2}  ;

to get:
_____________________________________________________
  →    a   =  | \sqrt{25 - b^2} |  ;

  →    a   =  ±  \sqrt{25 - b^2}  ; 
  
  →  which is:  Answer choice:  [C]:  " a =  ±  \sqrt{25 - b^2}  " .
______________________________________________________
8 0
3 years ago
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