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katovenus [111]
3 years ago
13

Fred buys a binder for $4.50 and six reams of paper. Latasha buys an ink cartridge for $17.50 and four reams of paper. Both spen

d the same amount of money. What is the price of one ream of paper?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

The the price of one ream of paper is $6.5.

Step-by-step explanation:

Here, Let us assume the cost of one ream of paper  = $  m

<u>The money spent by Fred:</u>

The money spent on a  binder  = $4.50

The money spent on 6 ream of papers  =  6 x ( cost of 1 ream )

= 6 x ($m) = 6 m

⇒The total money Fred spent  = Money spent on (binder + 6 ream of papers)  

= 4.50 + 6 m  ....... (1)

<u>The money spent by Latasha:</u>

The money spent on a cartridge = $17.50

The money spent on 4 ream of papers  =  4 x ( cost of 1 ream )

= 4 x ($m) = 4 m

⇒The total money Latasha spent  = Money spent on (cartridge + 4 ream of papers)  

= 17 .50 + 4 m  .... (2)

Also, Both spend the same amount of money

⇒4.50 + 6 m = 17 .50 + 4 m   ( from (1) and (2))

or, 6 m - 4  m= 17. 50 - 4, 50

or, 2 m =  13

or, m = 13/ 2  = 6.5

So, the value of m = $6.5

Hence, the the price of one ream of paper is $6.5.

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Margo brought 7 pens from a book store some pens cost $3.00 EACH and the rest cost $4.00 . If she paid a total of 23.00 for the
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Answer:

5

Step-by-step explanation:

Margo bought 7 pens for $23.

Some pens are $3 and some $4.

We need to find how many $3 pens she bought.

Let the number of $3 pens be represented by p and let the number of $3 pens be represented by r. So:

p = $3  and r = $4

Now we know 7 pens were purchased so is we add the number of $3 pens purchased to the number of $4 pens purchased, we will get 7.

p + r = 7

We know that the total cost of the pens is $23 so that equation would be found by takign the $3 pen multiplied by the number of $3 pens purchsed added to the $4 pen multiplied by the number of $4 pens purchsed, which equals $23.

$3p + $4r = $23

Now we have 2 equations and 2 unknowns.

p + r = 7

$3p + $4r = $23

Let's solve for r in the first equation.

p + r = 7     Subtract p from both sides.

p - p + r = 7 - p   The p on the left cancels.

r = 7 - p

Now that we know r, we can substitute it into the second equation and solve for p.

$3p + $4r = $23

3p + 4( 7 - p) = 23       Multiply it out.

3p + 4*7 - 4*p = $23

3p + 28 - 4p = 23      Combine like terms.

3p  - 4p + 28 = 23

- 1p + 28 = 23       Subtract 28 from both sides.

- p + 28 - 28 = 23 - 28  

- p = - 5   Divide each side by -1

- p/- 1 = - 5/ - 1       The negative cancels on each side.

p = 5

We can see Margo bought 5 $3 pens.

For fun, let's solve for how many $4 pens she bought. We know p, so we plug it in the first equation and solve for r.

p + r = 7

5 + r = 7  Subtract 5 from each side

5 - 5 + r = 7 - 5

r = 7 - 5

r = 2

So Margo bought 5 $3 pens and 2 $4 pens!

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