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gladu [14]
4 years ago
7

3. The sum of three consecutive integers is 198. What is the 2nd integer?

Mathematics
1 answer:
prohojiy [21]4 years ago
6 0

Answer:

Let, the integers = x, x + 2, x+ 4

It is given that, x + x+2 + x+4 = -198

3x + 6 = -198

3x = -198 - 6

x = -204/3

x = -68

Largest number, x+4 = -68+4 = -64

In short, Your Answer would be: -64

Guess and check works here. Since the sum is negative, we know that the 3 consecuticve even integers must be negative Guessing and checking, we find that the sequence is -64, -66, -68. We are trying to find the largest integer, which is -64. Hope That Helps!

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What is the value of 64 2/3?
Neporo4naja [7]

Answer:

\frac{194}{3}

Step-by-step explanation:

64 \frac{2}{3}

64 +  \frac{2}{3}

64 \times  \frac{3}{3}  +  \frac{2}{3}

\frac{64 \times 3}{3}  +  \frac{2}{3}

\frac{64 \times 3 + 2}{3}

\frac{192 + 2}{3}

\frac{194}{3}

<h3>Hope it is helpful...</h3>
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