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3 years ago

Can someone help me out plis

Advanced Placement (AP)

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Explanation:

It's difficult to define the planes as described in the image above ( it is usually described by at least3 coordinates) and to express the direction of a surface. Yet, considering the anterior hemiplan established by the BE direction for the rabbit and the coronal plan AD with AC direction for the human human we notice that they designate a plan that encompass the same body structures

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X-y=16 7x+2y=13 solving system of Equations by substitution

matrenka [14]

Answer:

The answer is " $x= -\frac{19}{5} \ and \ y= - \frac{99}{5}$ "

Explanation:

$\to x-y=16..........(a) \\\\ \to 7x+2y=13.........(b)\\$

In equation (a) multiply by 2 then subtract from the equation (b):

$7x+2y=13\\\\2x-2y=32\\\\- \ -\ = -\ \\\\5x = -19 \\\\x= -\frac{19}{5}$

put the value of x in equation (a):

$-\frac{19}{5} -y=16\\\\ -y=16 +\frac{19}{5}\\\\-y= \frac{80+19}{5}\\\\y= -\frac{99}{5}$

6 0

3 years ago

1) Calcula la diagonales de un poligono n lados. Heptágono: 2 puntos

ahrayia [7]

Answer:

El número de diagonales de un polígono de n lados se calcula mediante la siguiente fórmula:

$d = \frac{n\cdot (n-3)}{2}$ (1)

Donde:

$d$ - Cantidad de diagonales del polígono.

$n$ - Cantidad de lados del polígono.

Bajo esta fórmula, tenemos los siguientes resultados:

a) El heptágono tiene 14 diagonales.

b) El octágono tiene 20 diagonales.

c) El eneágono tiene 27 diagonales.

d) El decágono tiene 35 diagonales.

e) El pentadecágono tiene 90 diagonales.

Explanation:

La cantidad de diagonales de un polígono se puede determinar mediante la siguiente ecuación:

$d = \frac{n\cdot (n-3)}{2}$ (1)

Donde:

$d$ - Cantidad de diagonales del polígono.

$n$ - Cantidad de lados del polígono.

A continuación, calculamos la cantidad de diagonales de los siguientes polígonos:

Heptágono ( $n = 7$ )

$d = \frac{7\cdot (7-3)}{2}$

$d = 14$

El heptágono tiene 14 diagonales.

Octágono ( $n = 8$ )

$d = \frac{8\cdot (8-3)}{2}$

$d = 20$

El octágono tiene 20 diagonales.

Eneágono ( $n = 9$ )

$d = \frac{9\cdot (9-3)}{2}$

$d = 27$

El eneágono tiene 27 diagonales.

Decágono ( $n = 10$ )

$d = \frac{10\cdot (10-3)}{2}$

$d = 35$

El decágono tiene 35 diagonales.

Pentadecágono ( $n = 15$ )

$d = \frac{15\cdot (15-3)}{2}$

$d = 90$

El pentadecágono tiene 90 diagonales.

8 0

3 years ago

HELP PLEASE FASTT

SIZIF [17.4K]

Answer:

Today and in the 1970's inflation is very high

5 0

2 years ago

TO THE PERSON I TOLD TO CHECK MY WALL

Cloud [144]

We will build a wall and lock they door at night

7 0

3 years ago

Please help and show steps to answer

Rasek [7]

Answer is a

*The correct answer is IJ = JK

•explanation:

Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.

•Hence, we conclude the correct statement is IJ = JK

6 0

3 years ago