Answer:
B
Step-by-step explanation:
Recall that ![7^a\cdot 7^b = 7^{a+b}](https://tex.z-dn.net/?f=7%5Ea%5Ccdot%207%5Eb%20%3D%207%5E%7Ba%2Bb%7D)
So now
![7^{2/3} \cdot 7^{1/3}\\= 7^{\frac{2}{3}+\frac{1}{4}}\\=7^{\frac{8}{12}+\frac{3}{12}}\\=7^{11/12}](https://tex.z-dn.net/?f=7%5E%7B2%2F3%7D%20%5Ccdot%207%5E%7B1%2F3%7D%5C%5C%3D%207%5E%7B%5Cfrac%7B2%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D7%5E%7B%5Cfrac%7B8%7D%7B12%7D%2B%5Cfrac%7B3%7D%7B12%7D%7D%5C%5C%3D7%5E%7B11%2F12%7D)
The value of y will be equal to 4.
Reason : The length of the opposite cord is equal and therefore the distance from the centre to the cord will be equal.
Ans: 3rd option (4)
Hope this helps!
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Let absolute variation in the wait time at the bus stop = v
Variation = ±3 minutes
Average bus run through the city = 15 minutes
Hence, the minimum and maximum run values due to the variation can be modeled as:
|variation - average run| = ±3
|v - 15| = ±3
minimum : v = - 3 +. 15 = 12 minutes
Maximum : v = 3 + 15 = 18 minutes
Answer:
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