Answer:
a(n) = (3/5)a(n-1), where a(1) = 10 and n is 2 or greater.
Step-by-step explanation:
determine the common factor...The first term (10) by 3/5 results in the given second term (6); the third term is 3/5 of the second term (6), resulting in 18/5 (equivalent to 36/10 or 3.6/1, or just 3.6. Resulting in a(n) = (3/5)a(n-1).
the third term is 3.6, which, if mult. by (3/5), produces 2.16, as expected.
Thus, the recursive formula for this geometric sequence is a(n) = (3/5)a(n-1).
This is good only for a(1) = 10 and n = 2, 3, ....
Hope this helps you
16r^2+ 2r -4r
16r^2 - 2r
2r ( 8r -1)
I have no idea at all man I’m so sorry your math sucks
