Similar to 3250 times 2
Which is equal to 6500
Sin(4x) - sin(8x)
sin(2(2x)) - sin(2(4x))
2sin(2x)cos(2x) - 2sin(4x)cos(4x)
2[sin(x)cos(x)][cos²(x) - sin²(x)] - [2sin(2(2x))cos(2(2x))]
{2[sin(x)cos³(x) - sin³(x)cos(x)]} - [2[2sin(2x)cos(2x)][cos²(x) - sin²(x)]]
[2sin(x)cos³(x) - 2sin³(x)cos(x)] - {[2[2[sin(x)cos(x)][cos²(x) - sin²(x)]][cos²(x) - sin²(x)]}
[2sin(x)cos³(x) - 2sin³(x)cos(x)] - [2[2[sin(x)cos(x)][cos⁴(x) - 2cos²(x)sin²(x) - sin⁴(x)]]]]
[2sin(x)cos³(x) - 2sin³(x)cos(x)] - [2[2[sin(x)cos⁵(x) - 2sin³(x)cos³(x) + sin⁵(x)cos(x)]]]
2sin(x)cos³(x) - 2sin³(x)cos(x) - 4sin(x)cos⁵(x) + 8sin³(x)cos³(x) - 4sin⁵(x)cos(x)
The decay constant is i 0.1155, and there would be 16 mg left after 24 hours.
The relationship between the half-life, T₀.₅, and the decay constant, λ, is given by
T₀.₅ = 0.693/λ.
Solving for λ, we will multiply both sides by λ first:
(T₀.₅)(λ) = 0.693
Since we know the half life is 6 hours, this gives us:
6λ = 0.693
Dividing by 6, we have
λ = 0.693/6 = 0.1155.
The decay constant will be k in our decay formula, and N₀, the original amount of substance, is 250:
N(24) = 250e^(-0.1155*24) = 15.6 ≈ 16
Answer:
The 2 in the thousands place is 10 times more than the 2 in the hundreds place.
Step-by-step explanation:
Step-by-step explanation:
Storage facility => 12x²y³ • 4x⁴y²
Storage facility => 48x⁶y⁵