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3 years ago

Which is a correct step to solve the equation 1=−4+3/8x

Mathematics

1 answer:

padilas [110]3 years ago

5 0

Answer:

C. 8(1)=8(−4+3/8x)

Step-by-step explanation:

Given equation

1=−4+3/8x

in this equation in denominator we have 8x,

since we are solving for x we cannot eliminate it, but we have to eliminate 8 in denominator, so that there only numerator in equation and solving process becomes easier.

To eliminate 8,we need to multiply both side by 8, so as to balance the equation and also 8 from denominator gets cancelled in RHS.

1=−4+3/8x

multiply both side by 8

8(1)=8(−4+3/8x)

Thus, option c is correct one

8(1)=8(−4+3/8x)

solving it

8 = -32 + 3/x

adding both side 32

8+32 = -32 + 3/x -32

=> 40 = 3/x

=> x = 3/40

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What percent of 641 is 73?

alexira [117]

You can divide 73/641 to find the percent:

73/641 = 0.11388455...

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Now to make it into a percentage, multiple it by 100:

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4 years ago

Read 2 more answers

Is x = 6 a solution to the equation 5(x – 3) = x + 13?

deff fn [24]

Answer:

x=6 is not a solution

Step-by-step explanation:

We can substitute 6 as x to find out:

5(6-3)=6+13

first, because of PEMDAS we'll do 6-3

5(3)=6+13

multiply 5 by 3 and add 6 and 13

15=19

Since the statement is not true, that means that x=6 is not a solution

Hope this helps!

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3 years ago

How to solve 1/300:3 =1/120=x

netineya [11]

Answer:

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6 0

3 years ago

How do you Evaluate 6!

yan [13]

Answer:

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3 years ago

Apply the junction rule to the junction labeled with the number 1 (at the bottom of the resistor of resistance R2R2R_2). Answer

Ira Lisetskai [31]

Answer:

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Step-by-step explanation:

The image of the circuit is obtained online and attached to the question.

The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.

It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.

Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.

Σ I = 0

From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.

Hence,

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Hope this Helps!!!

5 0

4 years ago