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ozzi
3 years ago
8

Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model a sampl

e of 2700 bacteria selected from this population reach the size of 2976 bacteria in 2 hours find hourly growth rate parameter
Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0
5% per hour
I am still guessing
Needs to be verified
Hope it helps a little bit
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2 7/22 is the mixed number. 
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Figure 2<br> 4n<br> 5n -15<br> 90<br> 3n + 25<br> 6n - 10
icang [17]

Answer:

nI don't get exactly what your asking but if it's 4n + 5n - 15 + 90 + 3n + 25 + 6n - 10 simplfied then the answer is 18n + 90

Step-by-step explanation:

Add like terms

4n + 5n + 3n + 6n = 18n

-15 + 25 - 10 + 90 = 90

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How to simplify 29/40
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It can't be simplify
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Five years ago, John’s age was half of the age he will be in 8 years. How old is he now?
Stella [2.4K]

Answer:

18

Step-by-step explanation:

x-5=(x+8)/2

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6 0
3 years ago
| 7 + m | - 4 &gt; 8
cestrela7 [59]

Answer:

m > 5 or m < -19

Step-by-step explanation:

We are given the Inequality:

\displaystyle \large{ |7 + m|  - 4 > 8}

First, add both sides by 4.

\displaystyle \large{ |7 + m|  - 4 + 4 > 8 + 4} \\  \displaystyle \large{ |7 + m|  > 12}

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u>

\displaystyle \large{ |a|  =  \sqrt{ {a}^{2} } }

Given a = any expressions and b = any positive numbers, zero or any expressions.

\displaystyle \large{ |a|  =  b \longrightarrow a =  \pm b}

From the Inequality, change > to equal

\displaystyle \large{ 7 + m   =   \pm12}

Subtract 7 both sides.

\displaystyle \large{  7 - 7 + m   =  \pm12 - 7} \\ \displaystyle \large{  m   =   \pm12 - 7}

±12-7 can be 12-7 = 5 or -12-7 = -19

\displaystyle \large{  m   =   5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,

\displaystyle \large{  m    >  5, m < - 19}

3 0
3 years ago
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