The vertical asympototes of f(x) are at x = -6 and x = 6
Step-by-step explanation:
To find the vertical asymptote(s) of a rational function,
- Equate the denominator by 0
- Solve it for x
- If x = a, then the vertical asymptote is at x = a
∵ 
- Equate the denominator x² - 36 by 0
∵ x² - 36 = 0
- Add 36 to both sides
∴ x² = 36
- Take √ for both sides
∴ x = ± 6
∴ There are vertical asymptotes at x = -6 and x = 6
The vertical asympototes of f(x) are at x = -6 and x = 6
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Answer:
3150 feet for both
Step-by-step explanation:
correct?
Answer:
Range is 18.
Step-by-step explanation:
Range can be calculated by subtracting the smallest value of the data set from the largest value of the data set.
The values are:
13, 17, 18, 15, 12, 21, 10, 6, 8, 11, 3
Largest Value in this data set: 21
Smallest Value in this data set: 3
Range = Largest Value - Smallest Value
Range = 21 - 3
Range = 18
Let x,y be the two numbers.
Given that one number is 8 greater than another.
Let x be the smaller number ans y be the greater number.
That is y=x+8. Let this be the first equation.
And also given that product of the two numbers is 84.
That is x × y = 84, let us plugin y=x+8 here.
x × (x+8) = 84
x²+ 8x -84 = 0.
x²+12x-4x-84 = 0
x(x+12)-4(x+12) =0
(x-4)(x+12)=0
That is x= 4 or -12.
<h3>If x=4 , y= 4+ 8 = 12</h3>
<h3>If x= -12, y= -12+8 = -4 </h3>
Hence two positive numbers corresponding to given conditions are 4,12.
And two negative numbers corresponding to given conditions are -12,-4.
Step-by-step explanation:
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Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
