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nlexa [21]
3 years ago
11

Write an exponential function to model the situation. A population of 470 animals decreases at an annual rate of 12%.

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0
\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &470\\
r=rate\to 12\%\to \frac{12}{100}\to &0.12\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=470(1-0.12)^t\implies A=470(0.88)^t
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<h3>Answer:   </h3><h3>y + 10  =  - 5 (x - 2)  [point-slope form]  OR</h3><h3>y = - 5 x     [slope-intercept form]</h3><h2 /><h3>Step-by-step explanation:</h3>

<u>Identify the slope of the given line</u>

If we rewrite the equation given, we can easily identify the slope

                 x - 5y = 6

                    - 5y = - x + 6

                        y  = ¹/₅ x  - ⁶/₅

                                ∴ the slope of x - 5y = 6  is  ¹/₅

<u>Find the slope of the perpendicular line</u>  

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are negative-reciprocals of each other.

                 ⇒  since the slope of this line = ¹/₅

                      then the slope of the perpendicular line (m) =  - 5

<u>Determine the equation of perpendicular line</u>  

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:  

                             ⇒  y - (-10) =  - 5 (x - 2)

<h3>                                          ∴  y + 10  =  - 5 (x - 2)</h3><h3 />

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                                   since    y + 10  =  - 5 (x - 2)

<h3>                                                y  =  - 5 x</h3><h3 /><h3>∴ the slope-intercept equation of the perpendicular line is y + 10  =  - 5 (x - 2)  OR  y = - 5 x. </h3><h3 /><h3 />

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

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