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BlackZzzverrR [31]
3 years ago
12

A local coffee company recently started selling a new seasonal flavored drink. To determine how much the new flavor is liked by

the customers, an employee decided to stand just inside the door on Wednesday and ask every person entering to rate the new flavor on a scale from 1 to 5.
Mathematics
1 answer:
xeze [42]3 years ago
7 0
Chicken Chicken chicken
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4 children want to share 10 submarine sandwiches so that everyone gets the same amount. How much can each child have?​
kifflom [539]

Answer:

Each kid will get 2.5 submarine sandwiches

Step-by-step explanation:

4 0
3 years ago
Find the solution of this system of equations. Separate the x- and y- values with a comma. x-2y=-24 and x-y=4
defon
X - 2y = -24
x - y = 4

Isolate x in the first equation by adding 2y to both sides.
x = -24 + 2y  

Now plug in this value of x into the second equation.
(-24 + 2y) - y = 4
Solve. Combine all like terms, 2y - y.
-24 + y = 4
Add 24 to both sides to isolate y.
y = 28

Now plug y back into the first equation to find x.
x - 2(28) = -24
x - 56 = -24
Add 56 to both sides to isolate x.
x = 32

The solution is (32, 28).
6 0
3 years ago
Ms. Johnson earns $47,000 per year. She is paid weekly and puts 8% of her salary
Gekata [30.6K]
You divide 47,000 by 8. You should get 5,875. That should be the answer
3 0
3 years ago
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
JUAN SAYS, WHEN YOU PUT TOGETHER UNEQUAL GROUPS,YOU CAN ONLY ADD. IS HE CORRECT ? EXPLAIN.
Leno4ka [110]
If you treat multiplication as repeated a<span>ddition, then y</span>es, Juan is correct. Only equal groups can be multiplied.
5 0
3 years ago
Read 2 more answers
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