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Ksju [112]
3 years ago
10

Help pls it only the first question and I’m stuck already

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0
I Believe That The Answer Is 4
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Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
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3 years ago
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