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3 years ago

How many 4X4in squares will i need to cover 20ft high 10 ft wide wall

1 answer:

8 0

Find the area of the squares.
4 ×4 = 16

Find the area of the wall.
20 × 10 =200

Divide 200 by 16.
200 ÷ 16 = 12.5

You need 12.5 squares.

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2% ofthe students at Hamilton Middle School have red hair. There are 700 students at Hamilton Middle School How many students at

klemol [59]

You can use the equation x/700 * 2/100 to get your answer.
700 * 2 = 1400
1400/100 = 14
So 14 students at the school have red hair.

6 0

4 years ago

Read 2 more answers

Larry is 8 years older than his sister. In 3 years, he will be twice as old as she is now. How old are they now?

erma4kov [3.2K]

Let Sister's age now = s

So Larry is now s + 8

In THREE Years Sister = s + 3

Larry = {s + 8} + 3

But We are told that he will be TWICE as old as Sister is NOW!!!

So s + 11 = {2s}

Solve s = 11

So Sister is ELEVEN Years old and Larry is NINETEEN Years old.

6 0

3 years ago

Read 2 more answers

Kaitlin has 46 coins in her coin collection . She has albums that can hold 5 coins per page. The albums have 6 pages each. How m

Mademuasel [1]

Answer:

Hence, kaitlin will need 2 albums if she fills each page with her coins.

Step-by-step explanation:

The given information is:

Kaitlin has 46 coins in her coin collection.

She has albums that can hold 5 coins per page.

The albums have 6 pages each.

Now we are asked to find how many albums will be needed to fill each page with her coins.

As we know that 1 album has 6 pages.

1 page can hold=5 coins.

So, 1 album can old=6×5=30 coins.

Now 46-30=16 coins are left

So we will need one ore album so that these 16 coins could be placed in it.

Hence, kaitlin will need 2 albums if she fills each page with her coins.

6 0

3 years ago

World War I was also called because of the millions of casualties and the sheer brutal violence.

LuckyWell [14K]

WWI was also known as "The Great War"

7 0

3 years ago

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Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(

BlackZzzverrR [31]

We can parameterize this part of a cone by

$\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle$

with $0\le u\le a$ and $0\le v\le2\pi$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv$

The area of this surface (call it $\mathcal S$ ) is then

$\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi$

6 0

3 years ago