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Zielflug [23.3K]
3 years ago
14

What is the measure of angle 1 in degrees?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

180

Step-by-step explanation: because the lines are straight which means it is a 180 degree angle  

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Jared owed his brother
Genrish500 [490]
What would be the question????
3 0
4 years ago
jason mixed 8ml of a salt solution with 11ml of a 47% salt solution to make a 43%salt solution. find the percent salt concentrat
choli [55]

Let x% be the salt concentration of first solution.

Then in 8ml, amount of salt = \frac{8x}{100}

Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.

amount of salt in 11ml of 47% salt solution is \frac{11*47}{100} = \frac{517}{100}

So, total amount of salt in new mixture = \frac{8x}{100} +\frac{517}{100} = \frac{8x+517}{100}

But given that this new solution is a 43% salt solution.

Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is \frac{19*43}{100} = \frac{817}{100}

Hence \frac{8x+517}{100} = \frac{817}{100}

            8x+517 = 817

             8x=817-517 = 300

          x= 300/8 = 37.5

Hence the salt concentration in the first solution is 37.5%

8 0
3 years ago
Which statement about|-8 is true?
Roman55 [17]

Answer:

Your second listed answer choice would be your answer.

7 0
3 years ago
Solve each inequality. Justify each step (y-) - 4 + 2y > 11
Anna11 [10]
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
4 0
3 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
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