CD, CE, HG, GF, AL, LB, AB, HF, DE. A line segment is comprised of any two points. The ones I listed are the ones specifically named in the picture.
If you know 6+6 you know 6+7 because 6+7 is 1 more than 6+6.
6+6=12 while 6+7=13.
Another way to look at it is 7+7=14 so 6+7 is 1 less than it making 6+7=13.
Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,
sin²(x) + cos²(x) = 1
we always take the positive square root when solving for either sin(x) or cos(x).
Given that cos(α) = √11/7 and sin(β) = √11/4, we find
sin(α) = √(1 - cos²(α)) = √38/7
cos(β) = √(1 - sin²(β)) = √5/4
Now, recall the sum identity for cosine,
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
It follows that
cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28
Answer:
C) – 1
Step-by-step explanation:
E = cos20º + cos40º + cos60º +cos80° + cos 100°+cos120° +cos140° +cos160º + cos180º
E= 0.9 + 0.76 + 0.5+0.17+(-0.17)+(-0.5)+(-0.76) + ( – 0.9 ) + (– 1 )
E= 0.9 + 0.76 + 0.5 +0.17 - 0.17 - 0.5 -0.76 – 0.9 – 1
E= – 1
So ; equal – 1
I hope I helped you^_^
Answer:
A. x = 50, y = 130, z = 130
Step-by-step explanation:
50 and z are adjacent angles,
Sum of adjacent angles = 180,
50 + z = 180
z = 180 - 50
z = 130
z and x are adjacent angles,
Sum of adjacent angles = 180,
x + z = 180
130 + x = 180
x = 180 - 130
x = 50
z and y are opposite angles,
Opposite angles are equal in a parallelogram,
z = y = 130
