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Maru [420]
3 years ago
5

CORRECT answer gets BRAINLIEST, RATES, THANKS ON PROFILE AND HERE, AND 15 POINTS.

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
The volume of the cylinder by definition is given by:
 V = pi * r ^ 2 * h
 Where,
 r: radio
 h: height
 Substituting values we have:
 V = 3.14 * (14/2) ^ 2 * 4.5
 V = 692.37 ft³
 Answer:
 
the volume of the pool is:
 
V = 692.37 ft³
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HELP ASAP PLZ PLZ PLZ I GIVE BRAINLIEST
Yuki888 [10]

Answer:

12

Step-by-step explanation:

We can see that the base TA is 4, and the second base RS is 2. We can see that the height is 4. The area of a trapezoid is:

A=\frac{h(b_1+b_2)}{2}

Using this, we can substitute, and get:

A=\frac{4\cdot(2+4)}{2} = \frac{24}{2} = 12

Hope it helps!!

5 0
3 years ago
24% of students in a class are girls. If there are less than 30 students in this class, how many students are there? How many gi
castortr0y [4]

Answer:

Step-by-step explanation:

The GCF (greatest common factor) of 24 and 30 is 6.

30-30/6=25

25 students in the class

24% of 25 is 6

6 girls in the class

5 0
2 years ago
Each side of the equilateral triangle shown is 3 inches long. What is the height of the triangle?
rodikova [14]

•  measure of the side:   s = 3 in


You can find the height  h  by this formula:

          s · √3
h  =  ————
              2

          3 · √3
h  =  ————
              2

           3√3
h  =  ————  in     (exact value)
             2


Using  √3 ≈ 1.73,

           3 · 1.73
h  ≈  —————
                2

           5.19
h  ≈  ————
             2

h ≈ 2.60 in   (approximate value)


I hope this helps. =)

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to the expression shown 3^7 times 3^-4
lapo4ka [179]

Answer:

3/11

Step-by-step explanation:

Si los denominadores son iguales solo se coloca el mis mos y se suma los de arriba

6 0
3 years ago
Find x to the nearest tenth.
Jlenok [28]

Answer:

x = 11.3

Step-by-step explanation:

This is a right isosceles triangle

x² + x² = 16²

2x² = 256

x² = 128

x = 11.3

6 0
2 years ago
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