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Eduardwww [97]
3 years ago
13

Describe the difference between the lytic cycle and lysogeny when bacteriophage infection occurs.

Biology
1 answer:
Shkiper50 [21]3 years ago
8 0
Both are methods of viral multiplication inside the host cell.
 Lytic cycle (which is more common) includes steps like:
<span>1. Infection of the host cell-virus attaches to the receptor of the host cell, penetrates it and releases its genetic material into the host cell.</span>
<span>2. Virus Multiplication-Virus incorporated its genetic material into the host’s and uses its metabolism to multiply. Viral genetic material replicates separately from the host DNA.</span>
<span>3. Cell Destruction-  Virus releases an enzyme that breaks the cell wall from within, thus destructing the host cell.</span>  
<span>Lysogenic cycle also includes steps of infection, penetration and incorporation of the genetic material. But, after the virus integrates its genetic material it becomes dormant, letting the host multiple and continue its normal activities. Viral genetic material replicates within the host DNA during the host cell's division, so the daughter host cells are infected too.<span> At some point, the virus is triggered, it multiplies and ultimately, destroys the host cells.</span></span>
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You are studying a population of ground squirrels. You trap 100 individuals and find 9 that have a light colored coat, and the r
Genrish500 [490]

The question is incomplete. Here is the complete question.

You are studying a population of ground squirrels. You trap 100 individuals and find 9 that have a light colored coat and the rest have a dark coat. You know that light coat color is recessive in ground squirrels. What is the allele frequency for the light coat allele  and the dark coat allele? How many of the dark coated individuals do you expect to be heterozygotes at the coat color gene? Assume the population is at H-W equilibrium.

Answer: Allele frequency for light coat: q = 0.3;

              Allele frequency for dark coat: p = 0.7;

             There will be 42 heterozygote;

Explanation: A population in H-W equilibrium is a population which doesn't change from one generation to the next if there are no disturbing factors, as migration or mutation.

It follows the equation: p^{2}+2pq+q^{2}=1.

p represents the frequency of the dominant allele;

q represents the frequency of the recessive allele;

2pq represents heterozygote individuals;

The sum of frequencies of both alleles must be 1, i.e.: p+q=1

For the population of squirrels:

  • Frequency of recessive allele

q^{2} = \frac{9}{100}

q = \sqrt{\frac{9}{100}}

q = 0.3

  • Frequency of dominant allele

p+q=1

p=1-q

p=1-0.3

p = 0.7

  • Frequency of heterozygote

2pq = 2*0.7*0.3 = 0.42

In a population of 100 individuals: 0.42*100 = 42

The allele frequency for the light coat is 0.3; for the dark coat is 0.7.

It is expected to have 42 heterozygote individuals in this population.

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3 years ago
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