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Mrrafil [7]
3 years ago
12

Find the rate of ounces of what I need for each packages of flavoring

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0
4. 12×23= 276 ounces <span>for 23 packages of flavoring</span>
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Pls helppp!!! -------
Gelneren [198K]

Answer:

∠ A ≈ 44.42°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos A = \frac{adjacent}{hypotenuse}  = \frac{AC}{AB} = \frac{5}{7} , then

∠ A = cos^{-1} (\frac{5}{7} ) ≈ 44.42° ( to the nearest hundredth )

5 0
3 years ago
If twice a number, n, is 5 less than the number squared, which of the following equations could be used to properly solve for n?
hjlf

Answer:

2n - 5 = n^2 (or n squared)

3 0
3 years ago
This isn't really a school-related question.It's more of a conflict I have with my self. So: I have a friend that constantly cop
ycow [4]
Well to be honest, you need to straight forward to her and tell her that you do not appreciate her copying you and tell her you dont want to be rude or anything, but this needs to stop.
8 0
3 years ago
What does this equation equal to
Lena [83]
The answer to the equation is 115
6 0
4 years ago
Read 2 more answers
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
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