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USPshnik [31]
2 years ago
13

The relationship between the set of points in a plane equidistant from point A

Mathematics
1 answer:
Rainbow [258]2 years ago
3 0

A circle is the set of all points in a plane that are equidistant from a given point called the center of the circle. We use the symbol ⊙ to represent a circle. The a line segment from the center of the circle to any point on the circle is a radius of the circle

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Carl and rose live in the same straight road. From their balconies they can see a flagpole in the distance. The angle that each
Andreyy89

Carl and Rose' balconies make up the base of an isosceles triangle.

Their distances from the flagpole is the same.

From the question, we understand that:

  • Carl and Rose live on a straight line
  • The measure of angle from each person's balcony to the flagpole is the same

The above highlights mean that:

The relationship between Carl and Rose' balconies and the flagpole is an isosceles triangle.

Where Carl and Rose' balconies form the base of the isosceles triangle.

Hence, their distances from the flagpole is the same.

Read more about distances at:

brainly.com/question/12961022

6 0
2 years ago
Help I was absent when she taught this
DedPeter [7]

Answer:

b

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
340 students went to the first school dance, the last school dance 306 students attended. What is the percent of change between
Fofino [41]

Answer:

10.59%

Step-by-step explanation:

percentage of change is given by

{(old number - new number)/old number} * 100

_________________________

given

no. of student  went to the first school dance = 340

no. of student  went to the last school dance = 306

Percentage of change between two dance

= ((no. of student  went to the first school dance - no. of student  went to the last school dance)/ no. of student  went to the fist school dance)*100

= (340 - 306)/340 *100

= (36/340 )*100 = 10.59%

The percent of change between the two dances 10.59%.

4 0
3 years ago
Can someone please helppp I’m very desperate this is due tonight! Please show me how you got the answer
vazorg [7]

Answer:

4) 216

5) 216%

6) It's just like the bird's eye view of the tank, exept it's 2d.

Step by step solutions:

4) Draw a cube. Draw another cube but smaller. Label sides of the big cube 6x and the small cube x. Find the volume of each, which are 216x^3 and x^3. Divide (216x^3)/(x^3) and you get 216 times.

5) It wants percentage of big over small, so redraw the diagrams from #4 and instead of x, set x as 2. So the big sides are 12 and the small sides are 2. But you should write the sides as 2*6 and 2. Then, you calculate the volumes: 12^3 = 1728 and 2^3 = 8. Percentage of small tank over big tank would be 8/1728, but we want the opposite. We want something bigger than 1. So, we take the reciprocal and we get  1728/8 % = 216%. All along, the times was the percentage.

6) Draw a cube and draw a cube or a rectangular prism, but be warned, we don't know exactly what shape it is. Hint: just do a cube with a little exagerated side length just in case teacher is bad. OK back to this. Then, draw a line through the cube/rectangle and you get a rectangle-like shape.

7 0
3 years ago
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
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