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2 years ago

The relationship between the set of points in a plane equidistant from point A

1 answer:

3 0

A circle is the set of all points in a plane that are equidistant from a given point called the center of the circle. We use the symbol ⊙ to represent a circle. The a line segment from the center of the circle to any point on the circle is a radius of the circle

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El cociente de b y 5

lord [1]

Seria 25/5 por que si lo divides seria 5X5=25 ok a ver si te sirve

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2 years ago

Please help im so confused??

Ann [662]

V = PI x r^2 x h/3

3.14 x 7^2 x 24/3

49 x 8 = 392

answer is 392PI units^3

answer is B

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3 years ago

Which is the same as moving the decimal point 3 places to the right in a decimal number?

BartSMP [9]

Multiplying the number by 1,000

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3 years ago

College Calculus - hyperbolic functions (see attachment)

morpeh [17]

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx $\int\limits^x_4 {g(t)} \, dt = g(x)$

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

6 0

3 years ago

Read 2 more answers

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

11 months ago