Answer:25,000 in 2 years at annual compound interest, if the rates for the successive years be 4% and 5% per annum respectively is: (1) Rs. 30,000 (2) Rs. 26,800 fa) Rs.
A=P[1+
100
r
]
n
⇒ A=Rs.25,000×(
100
106
)
3
⇒ 25,000×
50
53
×
50
53
×
50
53
⇒ A=Rs.29,775.40
⇒ CI=A−P
⇒ Rs.29,775.40−Rs.25,000
∴ CompoundInterest=Rs.4775.40.
Answer:
Step-by-step explanation:
C
Answer:
72π (in terms of pi)
Step-by-step explanation:
V = π·r²·h
Plug in the values.
V = π·3²·8
Solve.
V = 72π
To leave an equation in terms of pi, just square, multiply, and leave pi at the end.
3² = 9·8 = 72
72π
If you need the answer fully simplified, it is 226.19 (rounded up).
Answer:
Step-by-step explanation:
3x – y + 2z = 6 - - - - - - - - - 1
-x + y = 2 - - - - - - - - - - - - -2
x – 2z = -5 - - - - - - - - - - - -3
From equation 2, x = y - 2
From equation 3, x = 2z - 5
Substituting x = y - 2 and x = 2z - 5 into equation 1, it becomes
3(y - 2) – y + 2z = 6
3y - 6 - y + 2z = 6
3y - y + 2z = 6 + 6
2y + 2z = 12 - - - - - - - - - 4
3(2z - 5) – y + 2z = 6
6z - 15 - y + 2z = 6
- y + 6z + 2z = 6 + 15
- y + 8z = 21 - - - - - - - - - - 5
Multiplying equation 4 by 1 and equation 5 by 2, it becomes
2y + 2z = 12
- 2y + 16z = 42
Adding both equations
18z = 54
z = 54/18 = 3
Substituting z = 3 into equation 5, it becomes
- y + 8×3 = 21
- y + 24 = 21
- y = 21 - 24 = - 3
y = 3
Substituting y = 3 into equation 2, it becomes
-x + 3 = 2
- x = 2 - 3 = -1
x = 1
