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Advocard [28]
3 years ago
15

If x is 1/2 and y is 1/4.what is answer of 4x÷y​

Mathematics
2 answers:
Bumek [7]3 years ago
8 0

Answer:

8

Step-by-step explanation:

4x ÷ y

x = 1/2

y = 1/4

4(1/2) ÷ 1/4

4 × 1/2 = 2

2 ÷ 1/4

2 × 4 = 8

lubasha [3.4K]3 years ago
7 0

if u thik this ans is helpful then u can start following me...

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A restaurant offers a dinner special in which diners can choose anyone of three appetizers, anyone of four entries, anyone of fi
Ainat [17]

Answer:

4 meals , is this the ans

3 0
3 years ago
What property is shown in the following equation?<br><br> 17 + 8 + 3 = 17 + 3 + 8
ss7ja [257]

Answer:

The Commutative Law of Addition.

Step-by-step explanation:

Basically, this law says we can swap numbers over and still get the same number when we add. This has demonstrated exactly that.

Hope this helped!

3 0
3 years ago
Read 2 more answers
A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an
mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft  and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin C=\frac{AB}{AC}

Putting values,

\sin 30^\circ} =\frac{10}{AC}

We know, \sin 30^\circ}=\frac{1}{2}

\frac{1}{2} =\frac{10}{AC}

On solving we get,

AC= 20.0 ft

Thus, the length of rope is 20.0 ft

Hence, <u>option (1)</u> is correct.

8 0
3 years ago
Read 2 more answers
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
Help please. I need help with the last one
snow_lady [41]
(-1,4), (1,1), (3,-2)
6 0
4 years ago
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