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3 years ago

If we solve an equation for a variable x what should our final equation look like ?

Mathematics

1 answer:

Nesterboy [21]3 years ago

6 0

You can solve an easy equation in your head by using the multiplication table.

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Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

3 years ago

The length of a rectangle is five times it’s width if the area of the rectangle is 320m^2 find its perimeter

BlackZzzverrR [31]

Answer:

Perimeter of the rectangle = 96 meters.

Step-by-step explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area = 320 sq meters

Now, Area of a Rectangle = Length x Width

⇒ 320 = K x 5K

or, $5K^{2} = 320\\or, K^{2} = \frac{320}{5} = 64$

So, the vlue of K = 8 or, K = -8

But as K represents a length hence, K ≠ -8

So, the width of the rectangle = 8 meters

and the length of the rectangle = 8 x 5 = 40 meters

Now, Perimeter = 2(length + width)

= 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.

6 0

2 years ago

Six distinct integers are picked from the set {1, 2, 3,…, 10}. How many selections are there, in which the second smallest integ

Ksivusya [100]

Answer:

1680 ways

Step-by-step explanation:

Total number of integers = 10

Number of integers to be selected = 6

Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.

2 ways 1 way

Each of the line represent the digit in the integer.

After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840

Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways

Therefore, there are 1680 ways to pick six distinct integers.

6 0

3 years ago

Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.

galben [10]

Answer:

a = 112

Step-by-step explanation:

$a =s^{2} +3b-c$

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

$a =s^{2} +3b-c$

$a = 7^{2} +3*13-(-24)\\$

$a=49+39+24\\$

$a=88+24$

$a=112$

Hope this helps you.

Let me know if you have any other questions :-)

3 0

2 years ago

Equivalent ratio for 12/17

siniylev [52]

Answer: 24:34

Step-by-step explanation:

If you multiply the ratio by 2, for example, it will still be equal.

5 0

3 years ago