Answer:
The characteristics of industrial organic agriculture are:
- economies of scale and mechanization
- substitution of conventional inputs such as conventional fertilizer with organic fertilizers
- bagging technology makes the transport of organic salads possible
Explanation:
Pollan's book discusses how modern individuals have a disconnection between food and knowledge. Modern individuals just pick up their food and practically don't know anything about how that food got reached our tables.
The answer is: "management rights" .
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"In a unionized firm, the <u> management rights </u> clause of <span>the collective bargaining agreement typically retains for management the authority to impose reasonable rules for workplace conduct and to discipline employees for just cause."
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Answer:
C) a local school district
Explanation:
Many school districts already carry out similar policies through Local School Wellness Policy programs. Malnutrition negatively affects kids the most and that is why school districts are currently trying to fight it. Malnutrition is not simply not eating enough food, it means not eating nutritious food at the right amounts. Obese children can suffer from malnutrition, while a slender kid can have a proper and balanced nutrition.
So if someone is seeking for a grant to fight malnutrition, they should go to their local authorities first and get in touch with the school district.
Answer: Balance of Trade
Explanation:
<em>Balance of trade</em> is the difference between the value of exports from a country and the value of imports into the country. When the value of exports is greater than imports, the balance of trade is positive and the country has a <em>trade surplus</em>. While, when the value of exports is less than the value of imports, the balance of trade is negative and the country has a <em>trade deficit</em>.
In this case, Wichasha's exports is higher than the total value of its imports so, it has a trade surplus or positive balance of trade.
Hey There!:
Sample Mean = 4.4823
SD = 0.1859
Sample Size (n) = 7
Standard Error (SE) = SD/root(n) = 0.0703
alpha (a) = 1-0.99 = 0.01
t(a/2, n-1 ) = 3.7074
Margin of Error (ME) = t(a/2,n-1)x SE = 0.2606
99% confidence interval is given by:
Sample Mean +/- (Margin of Error)
4.4823 +/- 0.2606 = (4.222 , 4.743)
Hope this helps!
