Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
$5 each car
3 hours = 12 cars
÷3 ÷3
1 hours = 4 cars
×8 ×8
8 hours = 32 cars
32 cars × $5 per car =
$160
They earned $160 in 8 hours, from washing 32 cars.
Should be A I’ll show you what I did though it might not make sense because I kind of did it in a weird way but yeah that answer should be A hope this helps :)
Answer:
-8p ≥ -56
=> p ≤ 7
Step-by-step explanation:
Answer:WFG=116
Step-by-step explanation:
