Use PEMDAS. Start by eliminating the exponents. you should be left with 3 numbers on bottom and 3 on top
multiply them then divide
Answer:
i think its a yes
Step-by-step explanation:
Answer: neither
Explanation:
x^3 can be either even or odd
Ex: x = 2 then 2^3 = 8 = even
Ex: x = 3 then 3^3 = 27 = odd
x^2 can also be either even or odd
Ex: x = 2 then 2^2 = 4 = even
Ex: x = 3 then 3^3 = 9 = odd
Since both can be even and odd
Even/Odd + Even/Odd = Even/Odd
So the result will be either even or odd
Answer:
what is the question i dont see the link
Step-by-step explanation:
The correct option has been marked in the Figure below. A function 
from a set 
to a set 
is a relation that assigns to each element 
in the set exactly one element 
in the set . The set is the domain (also called the set of inputs) of the function and the set contains the range (also called the set of outputs).
For our correct option we have:
<u>Set A, Domain:</u>
Inputs: -2, 1, 0, 1, 2, 3
<u>Set B, Range:</u>
Outputs: -1, 0, 1, 2, 3
This is a function because this is a relation that assigns to each element in the set exactly one element in the set . So, the assignation is as follow:
- -2 (in x) matches to 0 (in y)
- -1 (in x) matches to 3 (in y)
- 0 (in x) matches to 2 (in y)
- 1 (in x) matches to -1 (in y)
- 2 (in x) matches to 0 (in y)
- 3 (in x) matches to 2 (in y)
