The back-work ratio much higher in the brayton cycle than in the rankine cycle because a gas cycle is the Brayton cycle, while a steam cycle is the Rankine cycle. Particularly, the creation of water droplets will be a constraint on the steam turbine's efficiency. Since gas has a bigger specific volume than steam, the compressor will have to work harder while using gas.
Recall the steady flow device's shaft work expression.
W =-∫ V dP +...
As it is in the pump (liquid) compared to turbine (superheated vapor) in the Rankine cycle, the specific volume in the compressor is not significantly less than the specific volume in the turbine in the Brayton cycle.
A thermodynamic cycle that transforms heat into mechanical energy is the Rankine cycle, often known as the Rankine vapor cycle.
The operation of various heat engines that use air or another gas as their working fluid is described by the Brayton cycle, a thermodynamic cycle.
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Answer:
The yam was the cornerstone of Mongol administration and allowed the Great Khan to run one of the largest empires in history.
Explanation:
The kidneys of human body are main component of the excretory system and removes waste. When kidneys are not capable of funtioning normally, a dialysis machine is used for removing unwanted substances from the blood. It maintains the levels of required ion, minerals and electrolyets in the blood.
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Answer:
ΔG'° for the coupled reaction = -16.7 kJ/mol
<em>Note: The question is missing some parts. The complete question is as follows:</em>
<em>The first reaction in glycolysis is the phosphorylation of glucose:
</em>
<em>
Pi+glucose⟶glucose−6−phosphate+H2O
</em>
<em>This is a thermodynamically unfavorable process, with ΔG∘′= +13.8kJ/mol. In a liver cell at 37 ∘C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each.</em>
<em>This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H+</em>
<em>What is the ΔG'° for the coupled reaction?</em>
Explanation:
The coupling of ATP hydrolysis which is a thermodynamically favourable reaction to the phosphorylation of glucose makes it favourable. Since the two reactions constitute a sequential reaction, their standard free energy changes are additive.
For ATP hydrolysis: ATP + H₂O ---> ADP + Pi ; ΔG'° = -30.5KJ/mol
For phosphorylation of glucose: Pi + glucose⟶glucose−6−phosphate + H2O ; ΔG'° = +13.8 kJ/Mol
For the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H⁺ ; ΔG'° = 13.8 + (-30.5) kJ/mol = -16.7 kJ/mol
Therefore, ΔG'° for the coupled reaction = -16.7 kJ/mol
Answer:
The equation of breakdown of glucose is
C6 H12 O6-> 6O2 + H2O + CO +38 ATP. Don't mind the unbalanced equation
