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makvit [3.9K]
3 years ago
8

Solve (s)(-3st)(-1/3)

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

Step-by-step explanation

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The sum of three consecutive even numbers is 114. what is the smallest of the three numbers?​
saul85 [17]

Answer:

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Step-by-step explanation:

Let's let n be any number.

If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.

So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

(2n)+(2n+2)+(2n+4)=114

Solve for n. Combine like terms on the left:

6n+6=114

Subtract 6 from both sides:

6n=108

Finally, divide both sides by 6. Therefore, the value of n is:

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Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

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