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nikklg [1K]
3 years ago
6

Liza is playing a game in which she earns 3 points for each correct response but loses 2 points for each incorrect response. She

missed the first 3 questions. Right now she just hopes to break even. Which statement is true? To break even, Liza must answer 3 questions correctly to cancel out the 3 she answered incorrectly. O To break even, Liza must answer 2 questions correctly to give her 6 points, because she now has 6 points a the result would be a score of 0. O To break even, Liza must answer 6 questions correctly to give her 6 points, because she now has 6 points a the result would be a score of 0. O To break even, Liza must answer 1 question correctly, because she needs 3 points to cancel out the 3 questio she answered incorrectly.​
Mathematics
2 answers:
nikitadnepr [17]3 years ago
6 0

Answer:

To break even, Liza must answer 2 questions correctly to give her 6 points, because she now has negative 6 points a the result would be a score of 0

Step-by-step explanation

multiply negative 2 by the 3 incorrect questions, and you get negative 6.

divide 6 by 3 to get 2 to find the number of questions she needs to make correct to break even.

Molodets [167]3 years ago
3 0

Answer:

To break even, Liza must answer 2 questions correctly to give her 6 points, because she now has negative 6 points a the result would be a score of 0

Step-by-step explanation

multiply negative 2 by the 3 incorrect questions, and you get negative 6.

divide 6 by 3 to get 2 to find the number of questions she needs to make correct to break even.

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Find the area of an equilateral triangle that has perimeter of 24 m. ​
mafiozo [28]

we know the perimeter is 24, and is an equilateral triangle, so it has three equal sides, so each side is 24 ÷ 3 = 8.

\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}~~ \begin{cases} s=side's\\ \qquad length\\ \cline{1-1} s = 8 \end{cases}\implies A=\cfrac{8^2\sqrt{3}}{4}\\\\\\ A=16\sqrt{3}\implies A\approx 24.71

6 0
4 years ago
How can we simplify the expression -(1-5n)-7n
dsp73
-(1-5n)-7n \\ \\ -1 + 5n - 7n \\ \\ -1 - 2n \\ \\ Answer: \fbox {-1 - 2n}
5 0
3 years ago
BRAINIEST AND YOU WILL GET 10 POINTS!
jenyasd209 [6]
1 - The value of p in the equation is p = 0.

2 - The simplified form of the equation is 3x = 1, the reason behind this is when you do the equation, you get x = 1/3. When you do the equation 3x = 1 you get x = 1/3 as well.

3 - The value of z in the equation is z = 13.

4 - In order to figure out what step he did something wrong on, we first need to solve the problem, the answer we will get is x = 2.
To do this the easy way, we can solve each step, and see what one wouldn't equal 2, which the step he did wrong is Step 2.
So, to do Step 2 correctly, it would be: Step 2 - 12x − 6 = 14 + 2x.
6 0
3 years ago
Solve each of the following systems using the linear combination method. Check your answers
Dvinal [7]
3x+5y=11 answer : 3x+5y-11=0

Step by step explanation:

3x+5y=11
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8 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
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