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Readme [11.4K]
3 years ago
10

What is the value of x? X^2=17

Mathematics
1 answer:
ddd [48]3 years ago
5 0

Answer:

x=sqrt(17), -sqrt(17)

Step-by-step explanation:

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Amy​'s car holds at most 18 gallons of gas. Now it has 6 gallons. Use pencil and paper. Explain how to find the amount of gas sh
marissa [1.9K]

Answer:

10 gallons

Amy​'s car's maximum capacity to hold gas = 19 gallons

present amount of gas  = 9 gallons

As the car's capacity is 19 gallons and present amount in tank is 9 gallons, so we can fill it as much as so that the amount in tank becomes 19 gallons.

let assume she fills x gallons

then x gallons and 9 gallons present earlier should be equal to 19 gallon, as the tank can not hold more than that.

lets write it mathematically

x + 9 = 19

subtracting 9 from both side

x + 9 - 9 = 19 - 9

=> x = 10

8 0
3 years ago
7
vitfil [10]

Step-by-step explanation:

Let's use the number Zero as a placeholder.

7 in the hundredths place,

0.07

5 in the thousands place,

5000.07

4 in the hundreds place,

5400.07

7a. Write the number.

5400.07

7b. Write in word form.

Five thousand four hundred and seven hundredth

7c. Write in expanded form.

5000 + 400 + 0.07

7d. Write as a fraction.

540007 / 100

5 0
3 years ago
The funcilon f(x) = -(x + 5)(x +
Arte-miy333 [17]

Answer:

all numbers less than or equal to -3.

Step-by-step explanation:

The original equation shown is in "root form", a form of a quadratic equation showing where it hits the x-axis. This form does not show, like a "standard form" quadratic equation does, the vertex of the quadratic. The standard form equation is shown below.

ax^2+bx+c

  1. a is a constant showing the vertical stretch or compression of the quadratic. Also it can show if the function is flipped based on if it has a negative symbol at the front.
  2. b isn't very important when graphing unless you want to convert the equation to root-form.
  3. c is the height of the vertex. This is very important to know for this question because the vertex is either the minimum or maximum of the quadratic.

If we want to solve this equation showing all our work, the best bet is converting our equation from root-form to standard-form, like so:

f(x)=-(x+5)(x+1)

  • distribute x and 5 into (x+1). Then take this and distribute the negative sign.

f(x)=-x^2-5x-x-5\\f(x)=-x^2-6x-5

  • This is our standard-form of the quadratic. Now we just need to determine the range of y values it has.
  • <em>Note: The answers are wrong based on the c value I have for this equation, so I'm going to just give the answer closest to this one.</em>

Based on the properties of a standard form equation I gave earlier, this equation will look like an upside down "U" with a maximum value of -5. Therefore (based on the <em>italicized </em>text above), the range of y values for this equation must be "all real numbers less than or equal to -3".

P.S: Message me with any questions or fixes I should make to my math.

7 0
3 years ago
The mean monthly rent of students at Oxnard University is $890 with a standard deviation of $206. John's rent is $1,395. What is
mezya [45]

Answer:

$299

Step-by-step explanation:

Rent+standard deviation 890+206= $1,096

John's rent: $1,395

Z-score: 1395 - 1096=$299

8 0
4 years ago
Read 2 more answers
In science class, the average score on a lab report is 82 points, with all students scoring within 3.2 points of the average. if
gregori [183]

The absolute value equation that represents the minimum and maximum scores is:

|x - 82| = 3.2.

<h3>What is the absolute value function?</h3>

The absolute value function is defined by:

  • f(x) = x, x ≥ 0.
  • f(x) = x, x < 0.

It measures the distance of a point x to the origin.

For this problem, the distance between the minimum and the maximum scores and the mean is of 3.2, that is, the difference between these scores x and the mean of 82 is of 3.2, hence the absolute value equation that represents this situation is given by:

|x - 82| = 3.2.

More can be learned about absolute value equations at brainly.com/question/24514895

#SPJ1

7 0
2 years ago
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