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Sindrei [870]
4 years ago
7

Find the limit of the function by using direct substitution.

Mathematics
1 answer:
serg [7]4 years ago
6 0

Answer:

Option a.

\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

Step-by-step explanation:

You have the following limit:

\lim_{x \to \frac{\pi}{2}{(3e)^{xcosx}

The method of direct substitution consists of substituting the value of \frac{\pi}{2} in the function and simplifying the expression obtained.

We then use this method to solve the limit by doing x=\frac{\pi}{2}

Therefore:

\lim_{x \to \frac{\pi}{2}}{(3e)^{xcosx} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})}

cos(\frac{\pi}{2})=0\\

By definition, any number raised to exponent 0 is equal to 1

So

\lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}(0)}\\\\

\lim_{x\to \frac{\pi}{2}}{(3e)^{0}} = 1

Finally

\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

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alexandr402 [8]

Step-by-step explanation:

-9 x s = 6

-9 x 6 =s

-54=s

s=-54

6 0
3 years ago
Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.​
trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

A=P\left (1+\dfrac{r}{n}\right)^{nt}

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}

A=2000\left (1.05\right)^{4}

A=2000\left (1.21550625\right)

A=2431.0125

Now, the compound interest is

C.I.=A-P

C.I.=2431.0125-2000

C.I.=431.0125

Therefore, the compound interest is Rs 431.0125.

3 0
3 years ago
Find the area of the shaded region
VikaD [51]

Answer:

Area of the shades region = 244.6 ft²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle ABCD- Area of the right angle triangle DEC

Area of the rectangle = Length × width

                                    = 29.8 × 13

                                    = 387.4 ft²

By applying Pythagoras theorem in the right triangle DEC,

(Hypotenuse)² = (leg 1)² + (leg 2)²

CD² = DE² + EC²

(29.8)² = DE² + (28)²

888.04 = DE² + 784

DE² = 888.04 - 784

DE = 10.2 ft

Area of ΔDEC = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(10.2)(28)

                        = 142.8 ft²

Area of the shades region = 387.4 - 142.8

                                             = 244.6 ft²

4 0
3 years ago
Given f(2) = 12, which of the following could be an equation of the function?
sergiy2304 [10]
Answer is B. f(x) = 4x + 4 When we use x=2 in this function f(2) = 4(2) + 4 f(2)= 8 + 4 f(2) = 12 So the answer is B.
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3 years ago
The product of (7x+2) and 20-3x/4<br><br> Please help me on this problem
RoseWind [281]

Answer:

1. (7x+2)

2. 2 - 3x/4

4 0
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