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SVEN [57.7K]
3 years ago
12

The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at

the fair. Jermaine spent his money only on ride tickets and fair admission. The price of the fair admission is the same for everyone. Use y to represent the total cost and x to represent the number of ride tickets.
(a) Define your variables.
(b) Write a linear equation that can be used to determine the cost for anyone who only pays for ride
tickets and fair admission.
(c) Explain your answer to Part 1b.
Mathematics
1 answer:
aniked [119]3 years ago
8 0

Hello Anna,

(a)

1.25 per ticket

? number of rides (x)

43.75 total cost (y)

Admission (z)


(b) Linear Equation - 1.25x + z = y


(c) Well you need to calculate the totaly number of rides that person took and add that to the admission cost.


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What is the value of the expression below when w = 3. 4w^2 - 7w - 8
Makovka662 [10]
<h2>Answer:<em> </em><em><u>w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110 </u></em></h2><h2><em><u> w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>

Step-by-step explanation:  The prime factorization of  4320   is

  2•2•2•2•2•3•3•3•5  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 4320   =  √ 2•2•2•2•2•3•3•3•5   =2•2•3•√ 30   =

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 √ 30   , rounded to 4 decimal digits, is   5.4772

So now we are looking at:

          w  =  ( -40 ± 12 •  5.477 ) / -34

Two real solutions:

w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757

or:

w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110

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Yakvenalex [24]

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Step-by-step explanation:

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\Delta s = s_2-s_1

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Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

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Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

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In the same manner we can look at the y components of those points to find the vertical displacement

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Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

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Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

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