Answer:
the solution is (9, -1).
Step-by-step explanation:
graph the two equations on a graphing calculator (i use a website called desmos) and the point of intersection is the solution.
i hope this helps! have a great day <3
Answer:
Step-by-step explanation:
Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
You have to distribute!
6(x) = 6x and 6(-6)=-36
So now you have 6x-36=-3(-x+3)
Now do the same on the other side.
-3(-x)=3x -3(3)=-9
So now, 6x-36=3x-9
Combine the like terms:
Subtract 3x in both sides.
6x-3x=3x
Now: 3x-36=-9
Add 36 in both sides.
3x=27
Divide by 3 on both sides to get x alone.
3x/3= x 27/3=9
X=9
Answer:
x ≈ 30.9 (Choice D)
Step-by-step explanation:
We can use cosine for solving this question:
cos (61°) = 15 / x
x = 15 / cos (61°)
x = 30.93998011
x ≈ 30.9 (Choice D)
